So basically when you click the right arrow then click the chat box (or in browser, new tabs)then your mouse Will keep running non stop.

Glitch? Or is it just an illusion that the administration had decided to put in-game to makes us go crazy for cocoa puffs.

Known issue but don't know if it's a thing with Flash or the game.

I honestly don't think admins would remove this cause this makes is so people can chat and run still at the same time :/ not really an issue either imo, never even really thought about it like a glitch, it's been around since the start of the game, right? I've forgotten by now.

Mousechris a dit :

I honestly don't think admins would remove this cause this makes is so people can chat and run still at the same time :/ not really an issue either imo, never even really thought about it like a glitch, it's been around since the start of the game, right? I've forgotten by now.

There's a lot of bugs that have been around since the start of the game though.

It's just the run-lock. There's a value in the code set to "1" when you run, and the game will keep making your mouse run so long as this value remains at 1. It never goes back to 0 if you click the chat while running, since the game doesn't know you released the key. You will have to show the game a release of input to make the mouse stop running. For example, tapping the same direction again after clicking back into the game. It's still 1 when you press the button, but it goes back to 0 as soon as you release it. Some people have problems accidentally triggering this bug but the easiest way to fix it is to tap the same direction and release the button again.

Jumping is the only action this doesn't apply to because it only makes your mouse jump as soon as the required input value stops becoming 0, and only once.

Basically, it's a common game bug. The exact same thing happens if you tab out of game while running.
There are several similar methods of code in the game that determine, for example, whether your mouse can jump again in midair or cannot.